AP EAMCET · PHYSICS · Thermal Properties of Matter
Two plates of same area are placed in contact. Their thickness as well as their thermal conductivities are in the ratio \(2: 3\). The outer surface of one plate is maintained at \(10^{\circ} \mathrm{C}\) and that of the other at \(0^{\circ} \mathrm{C}\). Temperature at the common surface is
- A \(0^{\circ} \mathrm{C}\)
- B \(25^{\circ} \mathrm{C}\)
- C \(5^{\circ} \mathrm{C}\)
- D \(6.5^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(C) \(5^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Given that, two plates are having same surface area \((A)\). Let \(K_1, K_2\) and \(t_1, t_2\) be their conductivities and thickness respectively, According to question, \[ \frac{K_1}{K_2}=\frac{t_1}{t_2}=\frac{2}{3}...(i) \] Since, the rate of flow of heat through both plates…
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