AP EAMCET · Chemistry · Solutions
At 293 K , methane gas was passed into 1 L of water. The partial pressure of methane is 1 bar . The number of moles of methane dissolved in 1 L water is \(\left(\mathrm{K}_{\mathrm{H}}\right.\) of methane \(=0.4 \mathrm{kbar}\) )
- A \(1.38\)
- B \(1.38 \times 10^{-2}\)
- C \(1.38 \times 10^{-3}\)
- D \(1.38 \times 10^{-1}\)
Answer & Solution
Correct Answer
(D) \(1.38 \times 10^{-1}\)
Step-by-step Solution
Detailed explanation
According to Henry's Law, \(\begin{aligned} & \mathrm{p}=\mathrm{K}_{\mathrm{H}} \times \mathrm{x} \\ & \mathrm{p}=\text { partial pressure } \\ & \mathrm{K}_{\mathrm{H}}=\text { Henery constant }\end{aligned}\) \(\mathrm{x}=\) mole fraction given \(\mathrm{p}=1 \text { bar }\)…
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