AP EAMCET · PHYSICS · Dual Nature of Matter
Two photons of energy \(2.5 \mathrm{eV}\) and \(3.5 \mathrm{eV}\) fall on a metal surface of work function \(1.5 \mathrm{eV}\). The ratio of the maximum velocities of the photoelectrons emitted from the metal surface is
- A 1 : 4
- B 2 : 1
- C 1 : 2
- D \(1: \sqrt{2}\)
Answer & Solution
Correct Answer
(D) \(1: \sqrt{2}\)
Step-by-step Solution
Detailed explanation
Using, the equation \(\frac{1}{2} m v_1^2=h v_{0_1}-\phi_0\) ...(i) and \(\frac{1}{2} m v_2^2=h v_{0_2}-\phi_0\) ...(ii) Dividing Eq. (i) by Eq. (ii) we get…
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