AP EAMCET · PHYSICS · Laws of Motion
A particle of mass \(m\) is suspended from a ceiling through a string of length \(L\). If the particle moves in a horizontal circle of radius \(r\) as shown in the figure, then the speed of the particle is
- A \(r \sqrt{\frac{g}{\sqrt{L^2-r^2}}}\)
- B \(g \sqrt{\frac{r}{\sqrt{L^2-r^2}}}\)
- C \(r \sqrt{\frac{g}{\sqrt{L^2+r^2}}}\)
- D \(g \sqrt{\frac{r}{\sqrt{L^2+r^2}}}\)
Answer & Solution
Correct Answer
(A) \(r \sqrt{\frac{g}{\sqrt{L^2-r^2}}}\)
Step-by-step Solution
Detailed explanation
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