AP EAMCET · Maths · Sequences and Series
The sum of all integers between 1 and 100 (both inclusive) which are divisible by 5 or 13 is
- A \(1349\)
- B \(1536\)
- C \(1237\)
- D \(1479\)
Answer & Solution
Correct Answer
(A) \(1349\)
Step-by-step Solution
Detailed explanation
\(S_5 = \frac{20}{2}(5+100) = 1050\) \(S_{13} = \frac{7}{2}(13+91) = 364\) \(S_{65} = \frac{1}{2}(65+65) = 65\) \(S = S_5 + S_{13} - S_{65} = 1050 + 364 - 65 = 1349\)
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