AP EAMCET · Maths · Functions
\(f: R \rightarrow R\) and \(g: R \rightarrow R\) are two functions such that \(f(x)=x^2\) and \(g(x)=\frac{1}{x^2}\), then \(x^4(f \circ g)(x)\) is equal to
- A 0
- B 1
- C \(x^4\)
- D \(x^2\)
Answer & Solution
Correct Answer
(B) 1
Step-by-step Solution
Detailed explanation
Given, \(f(x)=x^2\) and \(g(x)=1 / x^2\) \(\begin{aligned} f \circ g(x) & =f(g(x))=\left(\frac{1}{x^2}\right)^2=\frac{1}{x^4} \\ \therefore \quad x^4 f \circ g(x) & =x^4 \times \frac{1}{x^4}=1\end{aligned}\)
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