AP EAMCET · PHYSICS · Electrostatics
Two concentric hollow spherical shells have radii \(r\) and \(R(R \gg r)\). A charge \(Q\) is distributed on them such that the surface charge densities are equal. The electric potential at the centre is
- A \(\frac{Q(R+r)}{4 \pi \varepsilon_0\left(R^2+r^2\right)}\)
- B \(\frac{Q\left(R^2+r^2\right)}{4 \pi \varepsilon_0(R+r)}\)
- C \(\frac{Q}{(R+r)}\)
- D zero
Answer & Solution
Correct Answer
(A) \(\frac{Q(R+r)}{4 \pi \varepsilon_0\left(R^2+r^2\right)}\)
Step-by-step Solution
Detailed explanation
We know that, the surface charge densities is \[ \sigma=\frac{Q}{4 \pi\left(r^2+R^2\right)} \] The electric potential at the centre…
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