AP EAMCET · PHYSICS · Alternating Current
Capacitive reactance of a capacitor in an \(\mathrm{AC}\) circuit is 6 \(\mathrm{k} \Omega\). If the same capacitor is connected to an \(\mathrm{AC}\) source of double the frequency, the capacitive reactance will become
- A \(6 \mathrm{k} \Omega\)
- B \(3 \mathrm{k} \Omega\)
- C \(1.5 \mathrm{k} \Omega\)
- D \(8.5 \mathrm{k} \Omega\)
Answer & Solution
Correct Answer
(B) \(3 \mathrm{k} \Omega\)
Step-by-step Solution
Detailed explanation
As we know \(\chi_{\mathrm{C}} \propto \frac{1}{\omega} \Rightarrow \frac{\chi_{\mathrm{C}_2}}{\chi_{\mathrm{C}_1}}=\frac{\omega_1}{\omega_2} \Rightarrow \chi_{\mathrm{C}_2}=6 \mathrm{k} \Omega \times \frac{\omega}{2 \omega}=3 \mathrm{k} \Omega\)
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