AP EAMCET · Maths · Quadratic Equation
If the sum of two roots of \(x^3+p x^2+q x-5=0\) is equal to its third root, then \(p\left(p^2-4 q\right)=\)
- A \(-20\)
- B \(20\)
- C \(40\)
- D \(-40\)
Answer & Solution
Correct Answer
(C) \(40\)
Step-by-step Solution
Detailed explanation
\(x^3+p x^2+q x-5=0 \quad \alpha+\beta+\gamma=-p\) \(\Rightarrow 2 \alpha=-p \Rightarrow \alpha=\frac{-p}{2} \quad[\because \beta+\gamma=\alpha]\) \(\therefore \frac{-p^3}{8}+\frac{p^3}{4}-\frac{p q}{2}-5=0 \Rightarrow \frac{p^3}{8}+\frac{p q}{2}-5=0\)…
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