AP EAMCET · PHYSICS · Laws of Motion
Two blocks A and B of masses 2 kg and 4 kg respectively are kept on a rough horizontal surface. If same force of 20 N is applied on each block, then the ratio of the accelerations of the blocks \(A\) and \(B\) is (Coefficient of kinetic friction between the surface and the blocks is 0.3 and acceleration due to gravity \(=10 \mathrm{~m} \mathrm{~s}^{-2}\) )
- A \(1: 1\)
- B \(7: 2\)
- C \(1: 2\)
- D \(4: 3\)
Answer & Solution
Correct Answer
(B) \(7: 2\)
Step-by-step Solution
Detailed explanation
\(a_A = \frac{F - \mu_k m_A g}{m_A} = \frac{20 - 0.3 \times 2 \times 10}{2} = \frac{20 - 6}{2} = 7 \mathrm{~m} \mathrm{~s}^{-2}\) \(a_B = \frac{F - \mu_k m_B g}{m_B} = \frac{20 - 0.3 \times 4 \times 10}{4} = \frac{20 - 12}{4} = 2 \mathrm{~m} \mathrm{~s}^{-2}\)…
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