AP EAMCET · PHYSICS · Motion In One Dimension
The velocitydisplacement \((v-s)\) graph shows the motion of particle moving in a straight linè.
Velocity-displacement graph is a circle of radius \(2 \mathrm{~m}\) and centre is at \((2,0) \mathrm{m}\).
The value of acceleration for this particle at a point \((2-\sqrt{2}, \sqrt{2}) \mathrm{m}\) will be \(\mathrm{ms}^{-2}\).
- A \(\sqrt{2}\)
- B 4
- C 2
- D 3
Answer & Solution
Correct Answer
(A) \(\sqrt{2}\)
Step-by-step Solution
Detailed explanation
As, graph is a circle with centre \((2,0)\) and radius 2 , its equation is \[ \begin{aligned} (s-2)^2+(v-0)^2 & =2^2 \\ (s-2)^2+v^2 & =4 \end{aligned} \] Differentiating with respect to time, we get…
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