AP EAMCET · PHYSICS · Gravitation
The value of acceleration due to gravity at a height of \(4 R_E\) from surface of earth is \(R_E\) is radius of earth and acceleration due to gravity on the surface of the earth = \(10 \mathrm{~ms}^{-2}\) )
- A \(0.2 \mathrm{~ms}^{-2}\)
- B \(0.3 \mathrm{~ms}^{-2}\)
- C \(0.4 \mathrm{~ms}^{-2}\)
- D \(3 \mathrm{~ms}^{-2}\)
Answer & Solution
Correct Answer
(C) \(0.4 \mathrm{~ms}^{-2}\)
Step-by-step Solution
Detailed explanation
Acceleration due to gravity ' \(\mathrm{g}\) ' varies with height as \[ g^{\prime}=g\left(\frac{R}{R+h}\right)^2 \] Given \(\mathrm{R}+\mathrm{h}=5 \mathrm{R}\) and \(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\)…
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