AP EAMCET · PHYSICS · Kinetic Theory of Gases
The ratio of specific heats at constant pressure and at constant volume is \(\gamma\). To find out the degree of freedom, the expression is
- A \(f=\frac{2}{\gamma-1}\)
- B \(f=\frac{\gamma+1}{2}\)
- C \(f=\frac{2}{\gamma+1}\)
- D \(f=\frac{1}{\gamma+1}\)
Answer & Solution
Correct Answer
(A) \(f=\frac{2}{\gamma-1}\)
Step-by-step Solution
Detailed explanation
We know that, \(\gamma=\frac{C_p}{C_V}\) ...(i) Energy of \(N\) molecules of gas, \(U=\frac{f}{2} R T\) where, \(f\) is degree of freedom.…
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