AP EAMCET · PHYSICS · Waves and Sound
The equation of a transverse wave propagating along a stretched string of length 80 cm is \(\mathrm{y}=1.5 \sin \left\{\left(5 \times 10^{-3} \mathrm{x}\right)+20 \mathrm{t}\right\}\), here ' x ' and ' y ' are in cm and the time ' t ' is in second. If the mass of the string is 3 g, then the tension in the string is
- A 12 N
- B 4 N
- C 6 N
- D 8 N
Answer & Solution
Correct Answer
(C) 6 N
Step-by-step Solution
Detailed explanation
\(k = 5 \times 10^{-3} \text{ cm}^{-1}\), \(\omega = 20 \text{ rad/s}\) \(v = \frac{\omega}{k} = \frac{20}{5 \times 10^{-3}} = 4000 \text{ cm/s} = 40 \text{ m/s}\) \(\mu = \frac{m}{L} = \frac{3 \times 10^{-3} \text{ kg}}{0.80 \text{ m}} = 0.00375 \text{ kg/m}\)…
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