AP EAMCET · PHYSICS · Mechanical Properties of Solids
The work done on a wire of volume of \(2 \mathrm{~cm}^3\) is \(16 \times 10^2 \mathrm{~J}\). If the young's modulus of the material of the wire is \(4 \times 10^{12} \mathrm{Nm}^{-2}\). Then the strain produced in the wire is
- A 0.03 m
- B 0.04 m
- C 0.01 m
- D 0.02 m
Answer & Solution
Correct Answer
(D) 0.02 m
Step-by-step Solution
Detailed explanation
\begin{aligned} & \mathrm{W}=16 \times 10^2 \mathrm{~J}, \mathrm{~V}=2 \mathrm{~cm}^3=2 \times 10^{-6} \mathrm{~m}^2 \\ & \mathrm{Y}=4 \times 10^{12} \mathrm{Nm}^{-2} \\ & \therefore \quad \mathrm{~W}=\frac{1}{2} \mathrm{y} \varepsilon^2 \mathrm{~V} \Rightarrow…
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