AP EAMCET · PHYSICS · Magnetic Effects of Current
An isosceles triangular current carrying loop is kept perpendicularly in a uniform magnetic field \(\overrightarrow{\mathrm{B}_{\mathrm{o}}}\) as shown in figure. The force on the loop due to magnetic field is
- A ILB \(_0 \cos \theta\)
- B 2 ILB \(_0 \cos \theta\)
- C \(0\)
- D ILB \(_0 \sin \theta\)
Answer & Solution
Correct Answer
(C) \(0\)
Step-by-step Solution
Detailed explanation
As the three forces are at \(120^{\circ}\) w.r.t. each other as shown above, so \(\overrightarrow{\mathrm{F}}_{\text {net }}=0\).
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