AP EAMCET · PHYSICS · Thermodynamics
If 2 moles of an ideal monoatomic gas at a temperature of \(27^{\circ} \mathrm{C}\) is mixed with 4 moles of another ideal monoatomic gas at a temperature of \(327^{\circ} \mathrm{C}\), then the temperature of mixture of the two gases is
- A \(300^{\circ} \mathrm{C}\)
- B \(227^{\circ} \mathrm{C}\)
- C \(233^{\circ} \mathrm{C}\)
- D \(327^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(B) \(227^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
\(T_1 = 27 + 273 = 300 \, \mathrm{K}\) \(T_2 = 327 + 273 = 600 \, \mathrm{K}\) \(T_{mix} = \frac{n_1 T_1 + n_2 T_2}{n_1 + n_2}\) \(T_{mix} = \frac{(2)(300) + (4)(600)}{2 + 4} = \frac{600 + 2400}{6} = \frac{3000}{6} = 500 \, \mathrm{K}\)…
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