AP EAMCET · PHYSICS · Magnetic Properties of Matter
The relation between \(\mu\) and \(H\) for a specimen of iron is \(\mu=\left[\frac{0.4}{H}+12 \times 10^{-4}\right] \mathrm{Hm}^{-1}\). The value of H which produces flux density of 1 T will be ( \(\mu=\) magnetic permeability, \(\mathrm{H}=\) magnetic intensity)
- A \(250 \mathrm{Am}^{-1}\)
- B \(500 \mathrm{Am}^{-1}\)
- C \(750 \mathrm{Am}^{-1}\)
- D \(10^3 \mathrm{Am}^{-1}\)
Answer & Solution
Correct Answer
(B) \(500 \mathrm{Am}^{-1}\)
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