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AP EAMCET · PHYSICS · Magnetic Properties of Matter

The relation between \(\mu\) and \(H\) for a specimen of iron is \(\mu=\left[\frac{0.4}{H}+12 \times 10^{-4}\right] \mathrm{Hm}^{-1}\). The value of H which produces flux density of 1 T will be ( \(\mu=\) magnetic permeability, \(\mathrm{H}=\) magnetic intensity)

  1. A \(250 \mathrm{Am}^{-1}\)
  2. B \(500 \mathrm{Am}^{-1}\)
  3. C \(750 \mathrm{Am}^{-1}\)
  4. D \(10^3 \mathrm{Am}^{-1}\)
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(B) \(500 \mathrm{Am}^{-1}\)

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For iron specimen,…
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