AP EAMCET · PHYSICS · Mechanical Properties of Solids
The ratios of lengths, areas of cross-section and Young's modulii of steel to that of brass wires shown in the figure are \(a, b\) and \(c\) respectively. The ratio of increase in the lengths of brass to that of steel wires is [Assume that the masses of steel and brass wires are negligible]
- A \(\frac{4 a}{7 b c}\)
- B \(\frac{7 b c}{4 a}\)
- C \(\frac{4 b c}{7 a}\)
- D \(\frac{7 a}{4 b c}\)
Answer & Solution
Correct Answer
(C) \(\frac{4 b c}{7 a}\)
Step-by-step Solution
Detailed explanation
Now, \[ T^{\prime}=T+3 g \Rightarrow T=4 g \] So, \(T^{\prime}=7 \mathrm{~g}\) So, \(\frac{F_S}{F_B}=\frac{T^{\prime}}{T}=\frac{7}{4}\) We know that,…
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