AP EAMCET · PHYSICS · Motion In Two Dimensions
The horizontal and vertical displacements of a projectile at time \(t\) are \(x=36 t\) and \(y=48 t-4.9 t^2\), respectively. Initial velocity of the projectile in \(\mathrm{m} / \mathrm{s}\) is
- A \(15\)
- B \(30\)
- C \(45\)
- D \(60\)
Answer & Solution
Correct Answer
(D) \(60\)
Step-by-step Solution
Detailed explanation
\[ x=36 t \] \[ y=48 t-4.9 t^2 \] Comparing with \(x=u \cos \theta t\) \[ y=u \sin \theta t-\frac{1}{2} g t^2 \] where, \(u=\) initial velocity \[ \begin{aligned} & u \cos \theta=36, \\ & u \sin \theta=48 \end{aligned} \]…
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