AP EAMCET · PHYSICS · Current Electricity
A heating element is designed to dissipate \(2400 \mathrm{~W}\) when connected to \(240 \mathrm{~V}\). The power it dissipates when it is connected to \(120 \mathrm{~V}\) is (Assume that resistance of the filament is constant)
- A \(600 \mathrm{~W}\)
- B \(1200 \mathrm{~W}\)
- C \(1800 \mathrm{~W}\)
- D \(400 \mathrm{~W}\)
Answer & Solution
Correct Answer
(A) \(600 \mathrm{~W}\)
Step-by-step Solution
Detailed explanation
Given, Rated power, \(P_R=2400 \mathrm{~W}\) Rated voltage, \(V_R=240 \mathrm{~V}\) So, resistance of element, \(R=\frac{V_R^2}{P_R} \quad\left(\because P=\frac{V^2}{R}\right)\) \(=\frac{240 \times 240}{2400}=24 \Omega\) when element is connected across \(120 \mathrm{~V}\)…
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