AP EAMCET · PHYSICS · Thermal Properties of Matter
The ratio energies of emitted radiation by a black body at \(600 \mathrm{~K}\) and \(933 \mathrm{~K}\) when the surrounding temperature is \(300 \mathrm{~K}\)
- A \(\frac{5}{16}\)
- B \(\frac{7}{16}\)
- C \(\frac{3}{16}\)
- D \(\frac{9}{16}\)
Answer & Solution
Correct Answer
(C) \(\frac{3}{16}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { } \frac{E_1}{E_2}=\frac{T_1^4-T_S^4}{T_2^4-T_S^4}\left[\because E=\sigma A T^4\right] \\ & \Rightarrow \frac{E_1}{E_2}=\frac{(600)^4-(300)^4}{(900)^4-(300)^4}=\frac{3}{16}\end{aligned}\)
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