AP EAMCET · PHYSICS · Gravitation
The radius of Earth is about \(6400 \mathrm{~km}\) and that of Mars is \(3200 \mathrm{~km}\), and mass of the Earth is about 10 times mass of Mars. An object weight \(200 \mathrm{~N}\) on the surface of Earth. Then, its weight on the surface of Mars will be
- A \(80 \mathrm{~N}\)
- B \(40 \mathrm{~N}\)
- C \(20 \mathrm{~N}\)
- D \(8 \mathrm{~N}\)
Answer & Solution
Correct Answer
(A) \(80 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
Given, radius of Earth and Mars are \(6400 \mathrm{~km}\) and \(3200 \mathrm{~km}\), respectively. Mass of Earth \(=10\) (Mass of Mars) \(M_e=10 M_m\) We know that, acceleration due to gravity at surface of a planet is \(g=\frac{G M}{R^2},\) where, \(M=\) mass of planet and…
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