AP EAMCET · PHYSICS · Ray Optics
The radius of curvature of the face of planoconvex lens is \(12 \mathrm{~cm}\) and its refractive index is 1.5. Then, the focal length of the lens is
- A \(26 \mathrm{~cm}\)
- B \(22 \mathrm{~cm}\)
- C \(24 \mathrm{~cm}\)
- D \(20 \mathrm{~cm}\)
Answer & Solution
Correct Answer
(C) \(24 \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
Given, refractive index of lens, \(\mu=1.5\) Radius of curved face, \(R_1=12 \mathrm{~cm}\) Radius of plane face, \(R_2=\infty\) Now, using the expression of focal length, \[ \frac{1}{f}=(\mu-1)\left[\frac{1}{R_1}-\frac{1}{R_2}\right] \] Substituting the values, we get…
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