AP EAMCET · PHYSICS · Dual Nature of Matter
The radiation of energy ' \(E\) ' falls normally on a perfectly reflecting surface. The momentum transferred to the surface is
- A \(\frac{E}{c}\)
- B \(\frac{2 E}{c}\)
- C \(\frac{E}{c^2}\)
- D \(\frac{2 E}{c^2}\)
Answer & Solution
Correct Answer
(B) \(\frac{2 E}{c}\)
Step-by-step Solution
Detailed explanation
Initial momentum, \(\mathrm{P}_1=\frac{\mathrm{E}}{\mathrm{c}}\) Final momentum, \(P_2=-\frac{E}{c}\) \(\therefore \quad\) Momentum transfer to the surface is \(\Delta P=P_1-P_2=\frac{E}{c}-\left(-\frac{E}{c}\right)=\frac{2 E}{c}\)
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