AP EAMCET · PHYSICS · Dual Nature of Matter
The maximum kinetic energy of the emitted photoelectrons from a photosensitive material of work function \(\phi\), when light of frequency ' \(V\) ' incidents on it is ' \(E\) '. If the frequency of the incident light is \(3 \mathrm{v}\), the maximum kinetic energy of the emitted photoelectrons is
- A \(3 \mathrm{E}+2 \phi\)
- B \(3 \mathrm{E}-2 \phi\)
- C \(2 \mathrm{E}+3 \phi\)
- D \(2 \mathrm{E}-3 \phi\)
Answer & Solution
Correct Answer
(A) \(3 \mathrm{E}+2 \phi\)
Step-by-step Solution
Detailed explanation
From the photoelectric equation \(\mathrm{E}=\mathrm{h} v-\phi\) ...(1) \(\mathrm{KE}_{\max }=3 \mathrm{~h} v-\phi\) ...(2) Solving equation (1) and (2), we have \(\mathrm{KE}_{\max }=3 \mathrm{E}+2 \phi\)
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