AP EAMCET · PHYSICS · Electrostatics
Four charges, each charge \(q\) coulomb are placed at points \((-1,0,0),(1,0,0),(0,-1,0)\) and \((0,1,0)\) in the \(x y\)-plane. The distance along the axes are measured in metres. The magnitude of the electric field at the point \(z=1 \mathrm{~m}\) on the \(Z\)-axis is
- A \(\frac{1}{2 \sqrt{2}} \frac{q}{\pi \varepsilon_0} \mathrm{~N} / \mathrm{C}\)
- B \(\frac{1}{4} \frac{q}{\pi \varepsilon_0} \mathrm{~N} / \mathrm{C}\)
- C \(\frac{q}{\pi \varepsilon_0} \mathrm{~N} / \mathrm{C}\)
- D \(\frac{q}{2 \pi \varepsilon_0} N / C\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{2 \sqrt{2}} \frac{q}{\pi \varepsilon_0} \mathrm{~N} / \mathrm{C}\)
Step-by-step Solution
Detailed explanation
The given situation is shown below. According to given situation we have to find electric field at point \(P(0,0,1)\). Distance of point \(P\) from each charges is equal to…
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