AP EAMCET · PHYSICS · Mechanical Properties of Solids
The length of a rod under longitudinal tension \(T_1\) is \(L_1\) and that under longitudinal tension \(T_2\) is \(L_2\). What is the actual length of the rod, in the absence of tensions?
- A \(\frac{L_1 T_1-L_2 T_2}{T_2-T_1}\)
- B \(\frac{L_1 T_2-L_2 T_1}{T_2+T_1}\)
- C \(\frac{L_1 T_1-L_2 T_2}{T_2+T_1}\)
- D \(\frac{L_1 T_2-L_2 T_1}{T_2-T_1}\)
Answer & Solution
Correct Answer
(D) \(\frac{L_1 T_2-L_2 T_1}{T_2-T_1}\)
Step-by-step Solution
Detailed explanation
Let, the natural length of wire be \(L_0\). Using Hooke's law, \[ Y=\frac{T L_0}{A \Delta L}...(i) \] where, \(Y\) is Young's modulus of elasticity, \(T\) is temperature, \(A\) is area and \(\Delta L\) is change in length, i.e. \(\Delta L=L-L_0\) From Eq. (i), we get…
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