AP EAMCET · PHYSICS · Thermodynamics
The heat supplied to a gas at a constant pressure of \(5 \times 10^5 \mathrm{~Pa}\) is 1000 kJ. If the volume of gas changes from \(1 \mathrm{~m}^3\) to \(2.5 \mathrm{~m}^3\), then the change in internal energy of the gas is
- A 250 kJ
- B 225 kJ
- C 200 kJ
- D 175 kJ
Answer & Solution
Correct Answer
(A) 250 kJ
Step-by-step Solution
Detailed explanation
\(W = P \Delta V\) \(W = (5 \times 10^5 \mathrm{~Pa}) (2.5 - 1) \mathrm{~m}^3 = 7.5 \times 10^5 \mathrm{~J} = 750 \mathrm{~kJ}\) \(\Delta U = Q - W\) \(\Delta U = 1000 \mathrm{~kJ} - 750 \mathrm{~kJ} = 250 \mathrm{~kJ}\)
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