AP EAMCET · PHYSICS · Alternating Current
The reactance of an inductor at \(50 \mathrm{~Hz}\) is \(10 \Omega\). The reactance of it at \(200 \mathrm{~Hz}\) is
- A \(10 \Omega\)
- B \(40 \Omega\)
- C \(2.5 \Omega\)
- D \(20 \Omega\)
Answer & Solution
Correct Answer
(D) \(20 \Omega\)
Step-by-step Solution
Detailed explanation
Given, initial frequency, \(f_1=50 \mathrm{~Hz}\) Initial reactance, \(X_1=10 \Omega\) Final frequency, \(f_2=200 \mathrm{~Hz}\) Final reactance, \(X_2=\) ? Since, reactance, \(X=\omega L\) \[ =2 \pi f L \]…
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