AP EAMCET · PHYSICS · Gravitation
The gravitational potential energy of a system of three masscs \(\mathrm{m}, 2 \mathrm{~m}\) and \(3 \mathrm{~m}\) pläced at three vertices of equilateral triangle of side ' \(a\) ' is
- A \(-11 \frac{\mathrm{Gm}}{\mathrm{a}}\)
- B \(-11 \frac{G m^2}{a^2}\)
- C \(-11 \frac{G m^2}{a}\)
- D \(-11 \frac{G m}{a^2}\)
Answer & Solution
Correct Answer
(C) \(-11 \frac{G m^2}{a}\)
Step-by-step Solution
Detailed explanation
The gravitational potential energy of a system is given by \[ \begin{aligned} & \mathrm{U}=-\frac{\mathrm{G}}{\mathrm{a}}\left[2 \mathrm{~m}^2+6 \mathrm{~m}^2+3 \mathrm{~m}^2\right] \\ & \mathrm{U}=-11 \frac{\mathrm{Gm}^2}{\mathrm{a}} \end{aligned} \]
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