AP EAMCET · PHYSICS · Laws of Motion
Two blocks A and B of masses \(5 \mathrm{~kg}\) and \(10 \mathrm{~kg}\) respectively are placed as shown in the figure. The coefficient of friction between all the surfaces is 0.2 . Then the acceleration of the block B is $\left(\mathrm{g}=10
- A \(2.6 \mathrm{~ms}^{-2}\)
- B \(47 \mathrm{~ms}^{-2}\)
- C \(26 \mathrm{~ms}^{-2}\)
- D \(4.7 \mathrm{~ms}^{-2}\)
Answer & Solution
Correct Answer
(D) \(4.7 \mathrm{~ms}^{-2}\)
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