AP EAMCET · PHYSICS · Units and Dimensions
The dimensional formula of a physical quantity represented by \(\frac{\mathrm{e}^2}{4 \varepsilon_0 \mathrm{~h}}\) is
[e is the charge of electron, \(\varepsilon_0\) is the permittivity of free space, and \(\mathrm{h}\) is the Planck's constant]
- A \(\left[\mathrm{M}^1 \mathrm{~L}^1 \mathrm{~T}^{-1}\right]\)
- B \(\left[\mathrm{L}^1 \mathrm{~T}^{-1}\right]\)
- C \(\left[\mathrm{M}^1 \mathrm{~L}^{\mathrm{o}} \mathrm{T}^{-1}\right]\)
- D \(\left[\mathrm{M}^1 \mathrm{~L}^1 \mathrm{~T}^{-2}\right]\)
Answer & Solution
Correct Answer
(B) \(\left[\mathrm{L}^1 \mathrm{~T}^{-1}\right]\)
Step-by-step Solution
Detailed explanation
\(\mathrm{e}^2=[\mathrm{q}]^2=[\mathrm{AT}]^2=\left[\mathrm{A}^2 \mathrm{~T}^2\right]\)…
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