AP EAMCET · Chemistry · Solutions
At \(T(\mathrm{~K})\), the vapour pressure of pure benzene is 0.85 bar. A non-volatile, non-electrolyte substance weighing \(0.5 \mathrm{~g}\) when added to \(39 \mathrm{~g}\) of benzene, the vapour pressure of the solution is 0.845 bar. The molar mass (in \(\mathrm{g} \mathrm{mol}^{-1}\) ) of the substance is
- A 180
- B 270
- C 160
- D 169
Answer & Solution
Correct Answer
(D) 169
Step-by-step Solution
Detailed explanation
If, \(p^{\circ}=\) vapour pressure of pure benzene. \(p=\) vapour pressure of solution.…
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