AP EAMCET · Maths · Probability
For two events and , a true statement among the following is
- A
- B
- C
- D
Answer & Solution
Correct Answer
(A)
Step-by-step Solution
Detailed explanation
We know that PBA=PA∩BPA ⇒PAPBA=PA∩B .......1 Now solving option A we get, PA¯∪B¯=PA∩B¯ {by demorgan's law} ⇒PA¯∪B¯=1-PA∩B ⇒PA¯∪B¯=1-PAPBA
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- If a number is drawn at random from the set \(\{1,3,5,7\), \(\ldots, 59\}\), then the probability that it lies in the interval in which the function \(f(x)=x^3-16 x^2+20 x-5\) is strictly decreasing, isAP EAMCET 2024 Easy
- If \(\left(\frac{\cos \theta+i \sin \theta}{\sin \theta+i \cos \theta}\right)^{2024}+\left(\frac{1+\cos \theta+i \sin \theta}{1-\cos \theta+i \sin \theta}\right)^{2025}=x+i y\), then the value of \(x+y\) at \(\theta=\frac{\pi}{2}\) isAP EAMCET 2025 Medium
- A player tosses two coins. He wins Rs. 1 if 1 head appears, Rs. 2 if 2 heads appear. But he loses Rs. 3 if no head appears. The mean of the prized money isAP EAMCET 2017 Hard
- \(\lim _{x \rightarrow-\infty} \frac{3|x|-x}{|x|-2 x}-\lim _{x \rightarrow 0} \frac{\log \left(1+x^3\right)}{\sin ^3 x}=\)AP EAMCET 2022 Easy
- \(\int \frac{d x}{x\left(x^2+1\right)^3}=\)AP EAMCET 2017 Hard
- If \(\int x^3 e^{2 x} d x=\frac{e^{2 x}}{8} f(x)+c\), then the sum of all the complex roots of \(f(x)=1\) isAP EAMCET 2019 Hard
More PYQs from AP EAMCET
- Identify the correct statements from the following.
I. At \(0 \mathrm{~K}\), the entropy of pure crystalline materials approach zero.
II. Entropy for the process, \(\mathrm{H}_2 \mathrm{O}(\mathrm{l}) \longrightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{g})\) decreases.
III. Gibb's energy is a state function.AP EAMCET 2022 Easy - If \(\frac{1}{x^4+x^2+1}=\frac{A x+B}{x^2+x+1}+\frac{C x+D}{x^2-x+1}\), then \(C+D\) is equal toAP EAMCET 2013 Medium
- If the vector \(\mathbf{a}=2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+6 \hat{\mathbf{k}}\) and \(\mathbf{b}\) are collinear and \(|\mathbf{b}|=21\), then \(\mathbf{b}\) equal to:AP EAMCET 2005 Easy
- If the vectors \(2 \overline{\mathrm{i}}+3 \overline{\mathrm{j}}+l \overline{\mathrm{k}},-3 \overline{\mathrm{i}}-2 \overline{\mathrm{j}}-4 l \overline{\mathrm{k}}\) and \(\overline{\mathrm{i}}-\overline{\mathrm{j}}+3 l \overline{\mathrm{k}}\) form a right angled triangle for a positive value of \(l\), then the length of its hypotenuse isAP EAMCET 2025 Medium
- In a Binomial distribution \(B(n, p)\), the sum and product of the mean and the variance are 5 and 6 respectively, then \(6(n+p-q)=\)AP EAMCET 2024 Medium
- If origin is the ortho-center of an equilateral triangle whose vertices are \(\bar{a}, \bar{b}, \bar{c}\) thenAP EAMCET 2022 Easy