AP EAMCET · Maths · Properties of Triangles
In a \(\triangle A B C\), if \(a \cos A=b \cos B\), where \(a \neq b\), then \(\triangle A B C\) is
- A Obtuse angled triangle
- B Equilateral triangle
- C Acute angled triangle
- D Right angled triangle
Answer & Solution
Correct Answer
(D) Right angled triangle
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { } a \cos A=b \cos B \\ & a\left(\frac{b^2+c^2-a^2}{2 b c}\right)=b\left(\frac{a^2+c^2-b^2}{2 a c}\right) \\ & \Rightarrow \frac{a}{b}\left(b^2+c^2-a^2\right)=\frac{b}{a}\left(a^2+c^2-b^2\right) \\ & \Rightarrow…
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