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AP EAMCET · PHYSICS · Dual Nature of Matter

The de Broglie wavelength of the most energetic photoelectrons emitted from a photosensitive metal of work function \(\phi\), when light frequency \(v\) incidents on it is \(\lambda\). Then \(\mathrm{v}=\) ( \(\mathrm{h}\) - Planck's constant, \(\mathrm{m}\) - mass of electron)

  1. A \(\frac{2 \phi}{\mathrm{h}}-\frac{\mathrm{h}}{\mathrm{m} \lambda^2}\)
  2. B \(\frac{2 \phi}{\mathrm{h}}+\frac{\mathrm{h}}{\mathrm{m} \lambda^2}\)
  3. C \(\frac{\phi}{h}+\frac{h}{2 m \lambda^2}\)
  4. D \(\frac{\phi}{\mathrm{h}}-\frac{\mathrm{h}}{2 \mathrm{~m} \lambda^2}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{\phi}{h}+\frac{h}{2 m \lambda^2}\)

Step-by-step Solution

Detailed explanation

By photoelectric effect…