AP EAMCET · Maths · Application of Derivatives
The tangent to the curve at the point meets the -axis at
- A
- B
- C
- D
Answer & Solution
Correct Answer
(C)
Step-by-step Solution
Detailed explanation
The tangent to the curve y=22x at the pts (0,1) meets the x-axies ⇒y=e2xdydx=2e2x dydx(0,1)=2e2(0)=2 eqn of tangent (y-y1)=dydx(x-x1) (y-1)=2(x-0) y=2x+1 meets the x-axies y=0 2x+1=0 x=-12 =(-12,0)
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