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AP EAMCET · PHYSICS · Work Power Energy

The bob of a simple pendulum of length 200 cm is released from horizontal position. If \(10 \%\) of its initial energy is lost due to air resistance, then the speed of bob at the mean position is
(Acceleration due to gravity \(=10 \mathrm{~m} \mathrm{~s}^{-2}\) )

  1. A \(6 \mathrm{~m} \mathrm{~s}^{-1}\)
  2. B \(3 \mathrm{~m} \mathrm{~s}^{-1}\)
  3. C \(12 \mathrm{~m} \mathrm{~s}^{-1}\)
  4. D \(2 \mathrm{~m} \mathrm{~s}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(6 \mathrm{~m} \mathrm{~s}^{-1}\)

Step-by-step Solution

Detailed explanation

\(PE_{initial} = mgL\) \(KE_{final} = PE_{initial} - 0.10 PE_{initial} = 0.90 mgL\) \(\frac{1}{2}mv^2 = 0.90 mgL\) \(v = \sqrt{1.8 gL}\) \(v = \sqrt{1.8 \times 10 \times 2} = \sqrt{36}\) \(v = 6 \mathrm{~m} \mathrm{~s}^{-1}\)
From AP EAMCET
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