AP EAMCET · Maths · Three Dimensional Geometry
The shortest distance between the skew lines \(\vec{r}(-\hat{i}-2 \hat{j}-3 \hat{k})+t(3 \hat{i}-2 \hat{j}-2 \hat{k})\) and \(\vec{r}=(7 \hat{i}+4 \hat{k})+s(\hat{i}-2 \hat{j}+2 \hat{k})\) is
- A 15
- B 0
- C 9
- D 16
Answer & Solution
Correct Answer
(C) 9
Step-by-step Solution
Detailed explanation
Given \(\begin{aligned} & \vec{r}=(-\hat{i}-2 \hat{j}-3 \hat{k})+t(3 \hat{i}-2 \hat{j}-2 \hat{k})=\vec{a}_1+t \vec{b}_1 \\ & \text { and } \vec{r}=(7 \hat{i}+4 \hat{k})+s(\hat{i}-2 \hat{j}+2 \hat{k})=\vec{a}_2+s \vec{b}_2\end{aligned}\) Now,…
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