AP EAMCET · PHYSICS · Dual Nature of Matter
The average number of photons emitted per second by a laser of power \(6.6 \times 10^{-3} \mathrm{~W}\) producing a light of wavelength \(600 \mathrm{~nm}\) is (Planck's constant, \(h=6.6 \times 10^{-34} \mathrm{~J}-\mathrm{s}\) )
- A \(2 \times 10^{16}\)
- B \(3 \times 10^{16}\)
- C \(4 \times 10^{16}\)
- D \(6 \times 10^{16}\)
Answer & Solution
Correct Answer
(A) \(2 \times 10^{16}\)
Step-by-step Solution
Detailed explanation
Photons emitted per second \(n=\frac{\text { Power }}{\text { Energy of } 1 \text { photon }}\) \(=\frac{P}{\left(\frac{h c}{\lambda}\right)}=\frac{P \lambda}{h c}\) Note \(\therefore h c=1240 \mathrm{eV}-\mathrm{nm}\) \(1 \mathrm{eV}=1.6 \times 10^{-19} \mathrm{~J}\) As given…
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