AP EAMCET · PHYSICS · Laws of Motion
A block \(P\) of mass \(M_P\) is in contact with another block \(Q\) of mass \(M_Q\) as shown in the fígure and they are placed on a smooth floor. Force on block Qis
- A \(\frac{M_p}{M_p+M_Q}\)
- B \(\frac{M_Q F}{M_p+M_Q}\)
- C \(\frac{M_\rho F}{M_Q}\)
- D \(\frac{M_Q F}{M_p}\)
Answer & Solution
Correct Answer
(B) \(\frac{M_Q F}{M_p+M_Q}\)
Step-by-step Solution
Detailed explanation
If \(a\) be the common acceleration of system of blocks on application of force \(F\). Free body diagram of block \(P\) and \(Q\) are given as Hence, for block \(P, F-R=M_P a\) For block \(Q, R=M_Q a\) Adding Eqs. (i) and (ii), we get…
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