AP EAMCET · Maths · Three Dimensional Geometry
Angle between the lines of intersection of the planes \(x-y=0,2 x+y+z=0\) and \(2 x-z=0, x+y-3 z=0\) is
- A \(60^{\circ}\)
- B \(45^{\circ}\)
- C \(30^{\circ}\)
- D \(90^{\circ}\)
Answer & Solution
Correct Answer
(D) \(90^{\circ}\)
Step-by-step Solution
Detailed explanation
Let the direction cosines of line of intersection of the planes \(x-y=0\) and \(2 x+y+z=0\) are \(a_1, b_1, c_1\) so \(a_1-b_1=0\) and \(2 a_1+b_1+c_1=0\) By cross-multiplication method, we have…
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