AP EAMCET · PHYSICS · Oscillations
The amplitude of a damped harmonic oscilator becomes \(50 \%\) of its initial value in a time of 12 s. If the amplitude of the oscillator at a time of 36 s is \(\mathrm{x} \%\) of its initial amplitude, then the value of \(x\) is
- A \(25\)
- B \(12.5\)
- C \(37.5\)
- D \(8\)
Answer & Solution
Correct Answer
(B) \(12.5\)
Step-by-step Solution
Detailed explanation
\(A(12 \text{ s}) = 0.5 A_0\) \(A(36 \text{ s}) = A_0 (0.5)^{(36/12)}\) \(A(36 \text{ s}) = A_0 (0.5)^3 = 0.125 A_0\) \(x = 0.125 \times 100 = 12.5\)
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