AP EAMCET · PHYSICS · Oscillations
Position of a \(3 \mathrm{~kg}\) mass moving along the \(X\)-axis is given by \(x=0.3 \cos (\omega t) \mathrm{m}\). If \(K(t)\) denotes the kinetic energy at time \(t\).
Then the value of \(\frac{K\left(\frac{\pi}{6 \omega}\right)}{K\left(\frac{\pi}{3 \omega}\right)}\) is
- A \(1 / 3\)
- B \(1 / 2\)
- C \(\sqrt{3} / 2\)
- D \(\sqrt{3}\)
Answer & Solution
Correct Answer
(A) \(1 / 3\)
Step-by-step Solution
Detailed explanation
Given, position of particle of mass \((m=3 \mathrm{~kg})\) is \(x=0.3 \cos \omega t\) Velocity of particle, \(v=\frac{d x}{d t}\) \(\Rightarrow \quad v=\frac{d}{d t} 0.3 \cos \omega t\)…
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