AP EAMCET · Maths · Probability
If a discrete random variable X has the probability distribution \(P(X=x)=k \frac{2^{2 x+1}}{(2 x+1)!}, x=0,1,2 \ldots \infty\), then \(k=\)
- A \(\sinh 2\)
- B \(\sec 2\)
- C cosech 2
- D \(\cosh 2\)
Answer & Solution
Correct Answer
(C) cosech 2
Step-by-step Solution
Detailed explanation
\(\sum_{x=0}^{\infty} P(X=x) = 1\) \(k \sum_{x=0}^{\infty} \frac{2^{2 x+1}}{(2 x+1)!} = 1\) \(k \sinh(2) = 1\) \(k = \frac{1}{\sinh(2)} = \text{cosech}(2)\)
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