AP EAMCET · Maths · Hyperbola
If \(\mathrm{P}\left(\frac{\pi}{4}\right)\) and \(\mathrm{Q}\left(\frac{3 \pi}{4}\right)\) are two points on the hyperbola \(4 x^2-y^2-8 x-2 y-13=0\) in parametric form, then the distance between \(\mathrm{P}\) and \(\mathrm{Q}\) is
- A \(4 \sqrt{6}\)
- B \(10\)
- C \(8 \sqrt{3}\)
- D \(5\)
Answer & Solution
Correct Answer
(A) \(4 \sqrt{6}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text {} \because 4 x^2-y^2-8 x-2 y-13=0 \\ & \Rightarrow 4(x-1)^2-(y+1)^2=16 \\ & \Rightarrow \frac{(x-1)^2}{4}-\frac{(y+1)^2}{16}=1 \end{aligned}\) Which can be parametrized as: \(x=1+2 \sec \theta, \quad y=-1+4 \tan \theta\) Now,…
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