AP EAMCET · PHYSICS · Mechanical Properties of Solids
One end of a wire of \(8 \mathrm{~mm}\) radius and \(100 \mathrm{~cm}\) length is fixed and the other end is twisted through an angle of \(45^{\circ}\). The angle of shear is
- A \(0.36^{\circ}\)
- B \(0.12^{\circ}\)
- C \(3.6^{\circ}\)
- D \(1.2^{\circ}\)
Answer & Solution
Correct Answer
(A) \(0.36^{\circ}\)
Step-by-step Solution
Detailed explanation
Given, radius of wire \[ \begin{aligned} r & =8 \mathrm{~mm} \\ & =8 \times 10^{-3} \mathrm{~m} \end{aligned} \] Length of wire, \(l=100 \mathrm{~cm}=1 \mathrm{~m}\) Twist, \(\phi=45^{\circ}\) Let shear angle be \(\theta\). and…
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