AP EAMCET · PHYSICS · Oscillations
Assertion (A) In S.H.M kinetic and potential energy become equal when the distance is \(1 / \sqrt{2}\) times its amplitude. Reason (R) The potential energy of a particle executing S.H.M is periodic with time period being maximum at the extreme displacement.
- A \(A\) and \(R\) are true. \(R\) is correct explanation of \(A\).
- B \(A\) and \(R\) are true. \(R\) is not correct explanation of \(A\).
- C \(A\) is true, but \(R\) is false
- D \(A\) is false but \(R\) is true
Answer & Solution
Correct Answer
(A) \(A\) and \(R\) are true. \(R\) is correct explanation of \(A\).
Step-by-step Solution
Detailed explanation
( In SHM, K. E of oscillator \(=\frac{1}{2} m \omega^2\left(a^2-y^2\right)\) P. E of oscillator \(=\frac{1}{2} m \omega^2 y^2\) (Here, \(a=\) amplitude and \(y=\) displacement) when, \(\mathrm{K} . \mathrm{E}=\mathrm{P} . \mathrm{E}\)…
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