AP EAMCET · PHYSICS · Thermodynamics
Two identical vessels \(A\) and \(B\) with frictionless pistons contain the same ideal gas at the same temperature and the same volume \(V\). The masses of gas in \(A\) and \(B\) and \(m_A\) and \(m_B\), respectively. The gases are allowed to expand isothermally to the same final volume \(2 V\). The change in pressures of the gas in \(A\) and \(B\) are found to be \(\Delta P\) and \(1.5 \Delta P\), respectively. Then
- A \(9 m_A=4 m_B\)
- B \(3 m_A=2 m_B\)
- C \(2 m_A=3 m_B\)
- D \(4 m_A=9 m_B\)
Answer & Solution
Correct Answer
(B) \(3 m_A=2 m_B\)
Step-by-step Solution
Detailed explanation
Let \(p_1\) and \(p_2\) are the initial and final pressures of the gas filled in \(A\). Then \( p_1=\frac{\mu_{\mathrm{A}} R T}{V} \text { and } P_2=\frac{\mu_A R T}{2 V} \) Dividing Eq. (ii) by (i), we get…
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